30x^2+80x=160

Solution for 30x^2+80x=160 equation:

30x^2+80x=160

We move all terms to the left:

30x^2+80x-(160)=0

a = 30; b = 80; c = -160;
Δ = b2-4ac
Δ = 802-4·30·(-160)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-160}{2*30}=\frac{-240}{60}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+160}{2*30}=\frac{80}{60}
=1+1/3
$